What happens to the value of i raised to odd powers?

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Multiple Choice

What happens to the value of i raised to odd powers?

Explanation:
When examining the powers of the imaginary unit \( i \), it is important to recognize the pattern that emerges as \( i \) is raised to successive powers. The fundamental property of \( i \) is that \( i^2 = -1 \). This relationship allows us to expand the powers of \( i \) systematically: - \( i^1 = i \) - \( i^2 = -1 \) - \( i^3 = i^2 \cdot i = -1 \cdot i = -i \) - \( i^4 = (i^2)^2 = (-1)^2 = 1 \) - Continuing this pattern, the next powers repeat the sequence: - \( i^5 = i \) - \( i^6 = -1 \) - \( i^7 = -i \) - \( i^8 = 1 \) From this information, we see that the powers of \( i \) form a cyclical pattern repeating every four powers: \( i, -1, -i, 1 \). Focusing specifically on the odd powers, we get: - For \( i^1 \), the result is \( i \

When examining the powers of the imaginary unit ( i ), it is important to recognize the pattern that emerges as ( i ) is raised to successive powers. The fundamental property of ( i ) is that ( i^2 = -1 ). This relationship allows us to expand the powers of ( i ) systematically:

  • ( i^1 = i )
  • ( i^2 = -1 )

  • ( i^3 = i^2 \cdot i = -1 \cdot i = -i )

  • ( i^4 = (i^2)^2 = (-1)^2 = 1 )

  • Continuing this pattern, the next powers repeat the sequence:

  • ( i^5 = i )

  • ( i^6 = -1 )

  • ( i^7 = -i )

  • ( i^8 = 1 )

From this information, we see that the powers of ( i ) form a cyclical pattern repeating every four powers: ( i, -1, -i, 1 ). Focusing specifically on the odd powers, we get:

  • For ( i^1 ), the result is ( i \
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